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0=9x^2-89x+182
We move all terms to the left:
0-(9x^2-89x+182)=0
We add all the numbers together, and all the variables
-(9x^2-89x+182)=0
We get rid of parentheses
-9x^2+89x-182=0
a = -9; b = 89; c = -182;
Δ = b2-4ac
Δ = 892-4·(-9)·(-182)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(89)-37}{2*-9}=\frac{-126}{-18} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(89)+37}{2*-9}=\frac{-52}{-18} =2+8/9 $
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